the horizontal distance between the two towers is 75 m and angle of depression of the top of the 1st tower as seen from top of 2nd ,which is 160m high ,is 45°.Find the height of the 1st tower.

second tower-160 m
distance - 74 m
when we draw an angle of depression to the top of the first tower from the second tower.we get the angles, 45,45,90.as in the ratio 1:1:√2.as we get the height if the first tower,160-75=85m.
is it right?
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2nd towr-160m
D b/w 2 twrs-75m
Nd angle of depression is 45 whn we see frm the top of 1st twr to the top of 2nd twr. So we find the height of 1st twr is 235m.is it ri8??
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Gh
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