The hybridization of the complex [CrCl2(NO2)2(NH3)2]– is :-
(1)    sp3d2
(2)    d2sp3
(3)    sp3d
(4)    Cannot be predicted 

Dear Student,

Electronic configuration of Cr = 3d‚Äč54s1
Electronic configuration of Cr4+= 3d2
Now, the six ligands will go into two 3d orbital, one 4s orbital and three 4p orbital giving d2sp3 hybridisation. 

Hence, the correct answer is (2)

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