The ionisation energy of hydrogen atom is 13.6 eV. Hydrogen atoms in the ground state are excited by monochromatic light of energy 12.1 eV. The spectral lines emitted by hydrogen atoms according to Bohr's theory will be. a. n=3 to n=1b. n=3 to n=2 c. n=2 to n=1d. n=4 to n= 1

Dear student,

En =   −13.6+12.1
     =   1.5eV 

∴n=  E1/En = 13.6/1.5 = 9
⇒n = 3

Thus transition occurs from 3rd to 1st orbit.
∴ spectral lines emitted =∑Δn

⇒∑(3−1)

⇒∑(2)

⇒1+2=3 

Hence (a) is the correct answer.

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