The ionization constant of a base (C2H5)3N is 6.4*10^-5. calculate its degree of dissociation in its 0.1 M solution when mixed with 0.01M NaOH solution.

Dear student

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6.4 X 10*3
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Degree of dissociation = Ka / Concentration of strong electrolyte having common ion added = (6,4 × 10^-5) / 0.01 = 6.4 × 10^-3
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Phele khud kar
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I don't know
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This is the solution:

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