The ionization potential for the electron in the ground state of the hydrogen atom is 13.6 eV/atom. What would be the ionization potential for the electron in the first excited stste of Li2+.
(a) 3.4 eV
(b) 10.2 eV
(C) 30.6 eV
(D) 6.8 eV

1. As we know :

    E = 13.6 Z2 1n21-1n12 eV atom-1
2. For the ionisation of Li2+ from n=2 to n= infinity we have :


 I.E = E = 13.6 ×32 ×122-12      = 30.6 eV
3. So, the correct option is (C).

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