The IUPAC name of Xe[PtF6] (with oxidation state).Explain how the oxidation state came.

Dear student,

The IUPAC name is xenon hexafluoroplatinate(V)
For the calculation of oxidation state of Pt.
This exists in the form of the ion as $[Pt{F}_6{]}^{-1}$
The oxidation of fluorine is -1
Let the oxidation state of Pt is x
Therefore,
x +  6 (-1) = -1
x -6 = -1
x = -1 + 6 = 5

The oxidation state comes out to be +5 or written as (V)

Regards