The kinetic energy of an object of mass , m moving with a velocity of 5m/s is 25J.what will be its kinetic energy when its velocity is doubled ?what will be its kinetic energy when its velocity is incrased three times

If we double the velocity of the object, then the Kinetic energy E_k becomes four times the initial value.

Hence, the kinetic energy of the object will become four times ,i.e, 25*4= 100J.

 Kinetic energy=1/2 m(v )square

25J                      =1/2 *m*(5)square

Therefore, mass=2 kg

the kinetic energy when its velocity is doubled=1/2 *m(2*v)square

=1/2*2*(5*2)square

=100 joule

And, the kinetic energy when its velocity is increased three =1/2 *m(3*v)square

=1/2*2*(3*5)square

=337.50 joule.

 First, we will calculate the mass 'm ' of the object.

Now, Kinetic energy = ¹ / ₂ mv ²

So, 25 = ¹ / ₂ x m x (5) ²

25 = ¹ / ₂ x m x 25

m = 2kg

When the velocity of the object is doubled, it becomes 5 x 2 = 10 m s ^-1

Now, Kinetic energy = ¹ / ₂ mv ²

= ¹ / ₂ x m x (10) ²

= ¹ / ₂ x 2 x 100

= 100 J

Thus, when the velocity of the object is doubled, then it 's Kinetic energy becomes 100 J.

When the velocity of the object is increased three times, it becomes 5 x 3 = 15m s ^-1

Now, Kinetic energy = ¹ / ₂ mv ²

= ¹ / ₂ x m x (15) ²

Kinetic energy=1/2 m(v )square

25J =1/2 *m*(5)square

Therefore, mass=2 kg

the kinetic energy when its velocity is doubled=1/2 *m(2*v)square

=1/2*2*(5*2)square

=100 joule

And, the kinetic energy when its velocity is increased three = 1/2 *m(3*v)square

=1/2*2*(3*5)square

=337.50 joule.