The largest term common to the sequence 1,11,21,31,.... to 100 terms and 31,36,41,46,..... to 100 terms is (A) 381 (B) 471 (C) 281 (D) none . Please give the solution alse.

The first sequence is , 1+11+21+31+41+51+61+71+81+91+....100 term.last term will be = 1+100-1×10=991and for the sequence 31+36+41+46+51+.....100 term last term will be = 31+100-1×5=526Now we have the common term as, 31+51+71+.....and nth term of this sequence will be=31+n-1×20=20n+11and this will be less than 526So 20n+11<52620n<515n<5152025.75 So n = 25Hence the largest common term = 20×25+11=511.

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