The length and radii of 3 wires of same metal are in the ratio 2: 3: 4 and 3:4:5 respectively. They are joined in parallel and included in a circuit having 5 Ampere current. Find current in each wire.

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As the resistance of wire is given byR=ρLA=ρLπr2So, R1:R2:R3=232:342:452or, R1:R2:R3=29:316:425And as for an electrical conductor, V=IR and in case of resistance in parallel,V=constant, I α 1RTherefore, I1:I2:I3=92:163:254or, I1:I2:I3=54:64:75But as I1+I2+I3=5 ASo, I1=554+64+75×54I1=5193×54=1.4 AI2=5193×64=1.66 AI3=5193×75=1.94 A

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5Amp current flows through all the three wires
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