# The length of the minute hand of a clock is 14 cm. Find the area swept by the minute hand in 5 minutes.

(22 /7 X 14 x14) 5

• -8

5 minutes= 5/60 = 1/12

1/12= 1/12 x 360= 30

area= pi r squared x theta/360= 22/7 x 14 x 14 x 30/360 = 154/3 = 51.33 cm sq.

• 24

length= 14 cm

angle= 5 * 6 = 30 degree                    {because, angle swept in 1 min = 60/360 = 6 degree}

area swept = 30/360 * 22/7 * 14 * 14

= 1/12 *22 * 2 * 14

= 154/3

= 51.33 cm^2

• 87

Thank you friends...:)

• -7

The minute hand of clock acts and radius of clock which is 14cm long.

Therefore angle made by min hand in 5 mins= 5/60 * 6/6  =  30'

Now Area swept by min hand = Area of Sector =

= 22/7 * 14 * 14 *  30/360

=  22 * 2 * 14 * 1/12

= 154/3  cm square or

51.333  cm square

• 23

length= 14 cm

angle= 5 * 6 = 30 degree

area swept = 30/360 * 22/7 * 14 * 14

= 1/12 *22 * 2 * 14

= 154/3p

= 51.33 cm^2

Hope u understan, thumbs up!!!

• 27

how does 154/3 come

• 1
1/12*22*2*14 = 154/3 Zayed Al Kabir... 12 and 22 get cut ( u can also cut 12 with 2 or 14 if u wish) then u have 1/6*11*2*14 then cut 6 with 2 or 14 then the denominator will be 3 and if u multiply the numerators then u will get 154 therefore u get 154/3... :)
• 4
thank u
• -6
thnk u so much......
• -7
area of sector = 0/360*/2
for 1 min =60/360=6
for 5min =5*6=30
area of sector=30/360*22/7*14*14
=1/3*11*14
=154/3
=51.33
• -6
area of sector for 1 min = 60/360=6
for 5 min=6*5=30
area of sector = 22/7*14*14*30/360
= 51.33
hope u understand have a blast
• -8
length=14 cm
angle made by minute hand in 5 minute = 360/12            because  in a clock 12 parts are there to complete 360o
= 30o
so, the area swept = 30o/360o * (14)2

= 1/12 *196
=  16.33 cm2

• 5
see here this is correct format

take length of minute hand as radius of circle i.e 14 cm

area swept by minute hand in 15 minutes therefore angle = 30 degrees

area = 30/360 * 22/7 * 14 * 14 =  51.33

hope it helps.
all the best for your exams.
• 9
51.33 cm^2
• -6
radius of hand of clock=14 cm
total angle in a clock = 360
total no. of minutes in an hour = 60 min
angle swept by a minute = 360/60 = 6
time given = 5 min
therefore, angle swept by 5 minutes = 6*5=30
area of sector = theeta/360*pie r square
= 30/360*22/7*14*14
= 51.33 sq.cm
• 7
As length=14

• -11
51.33 CM square
• -5
Hey 60/360 is 1/6 not 6 degrees
• -4
• -3
Plz check on dron study.com
• -1
The length of the minute hand of a clock is 14 cm. Find the area swept by the minute hand from 10 am to 10. 40 am
• -1
LENGTH OF MINUTE HAND OR RADIUS = 14
ANGLE= 360/12 = 30
AREA =  AREA OF SECTOR
30/360*22/7*14*14
=  22*7/3
= 154/3

• -1
So easy answer of this question
• -2
This is very easy and simple question
• -3
Are of a sector =8.75cm sq • -4 • 1
Final answer is = 51.33 cm square.
• -3
The final answer is = 51.33 cm square. • 17
56
• -3
After this 77×2 Divided by 3 =154÷3 =51 1÷3mixed fraction • 2 • 5
epution
• -1 • 0
1 hour=360 minutes so ,1 minute =360/60 • 1 • 0
Thats all • 1
Angle in between digits of clock ~360°/12=30 Area swept in 5 minutes = area of the hands from one position to next position Therefore area =30/360×(14^2)*π =51.34cm^2
• 0
jsickzo@ka9awyiauw
• -1
the length of the minute hand should be taken as the radius of a circle and to work out the area of the circle which comes to 616cm2. The area covered by minute hand in 5 minutes is 616/12 cm2
• 0
1min. make angle of 6?
So angle in 5 min. is 30?

So
Area swept by minute hand = 30??360??22?7 ?14?14
• 0
51.33 cm sq.
• 0
length= 14 cm

angle= 5 * 6 = 30 degree ? ? ? ? ? ? ? ? ? ?{because, angle swept in 1 min = 60/360 = 6 degree}

area swept = 30/360 * 22/7 * 14 * 14

? ? ? ? ? ? ? ? ? ? = 1/12 *22 * 2 * 14

? ? ? ? ? ? ? ? ? ? = 154/3

? ? ? ? ? ? ? ? ? ? = 51.33 cm^2
• 1 • 0