The length of the minute hand of a clock is 14 cm. Find the area swept by the minute hand in 5 minutes.
Length of the minute hand is 5cm.
Length of the minute hand is the Radius of the circular clock.
So r = 14cm
As the minute hand subtends 360? to cover 60 minutes.
Therefore,
Angle subtended by the minute hand in 1 minute = 360?/60? = 6?
So angle subtended by minute hand in 5 minutes is = 6 ? 5 = 30?
So we have angle subtended in 5 mins = 30?
Now,
Area swept in 5 minutes = Theta/360 ? ?r?
=> 30/360 ? 22/7 ? 14 ? 14
=> (22 ? 2 ? 14) / 12
=> 154 / 3
=> 51.33cm?
?Therefore area swept by the minute hand in 5 minutes = 51.33cm?
Length of the minute hand is the Radius of the circular clock.
So r = 14cm
As the minute hand subtends 360? to cover 60 minutes.
Therefore,
Angle subtended by the minute hand in 1 minute = 360?/60? = 6?
So angle subtended by minute hand in 5 minutes is = 6 ? 5 = 30?
So we have angle subtended in 5 mins = 30?
Now,
Area swept in 5 minutes = Theta/360 ? ?r?
=> 30/360 ? 22/7 ? 14 ? 14
=> (22 ? 2 ? 14) / 12
=> 154 / 3
=> 51.33cm?
?Therefore area swept by the minute hand in 5 minutes = 51.33cm?
- 0