The length of the perpendicular from the origin to the line is 7 and the line makes the angle of 150o with the positive direction of y-axis. Then find the equation of the line.

Angle made with positive y-axis =150°Angle made with positive x-axis =60° and 180°-60°=120°Let intercepts made by the line on x and y axis be a and b respectively.,i,eCoordinates are A(a,0) and B(0,b)Slope=tan 120°    and  Slope=tan 60° b-00-a=-3        b-00-a=3b=a3........(i)       b=-a3........(ii)equation of line:y-0=b-00-a(x-a)y=-3(x-a)      and y=3(x-a)3x+y-a3=0 and 3x-y-a3=0Now,dorigin=7Ax+By+cA2+B2=73.0±1.0-a33+1=7a3=±14equation of lines are:3x+y±14=0 and 3x-y±14=0

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