The line 4x+3y-12equal to 0 intersects x y at A B respectively

The line 4x+3y-12equal to 0 intersects x y at A B respectively 2.

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Please find below the solution to the asked query :


$$\begin{gathered} \mathrm{Area} \mathrm{of} \mathrm{triangle} \mathrm{AOB}=\frac{1}{2}\times \mathrm{base}\times \mathrm{height} \\ =\frac{1}{2}\times \mathrm{OA}\times \mathrm{OB} \\ =\frac{1}{2}\times 3\times 4 \\ =6 \mathrm{sq}. \mathrm{units} \end{gathered}$$

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