the line x + y = p meets the x-axis of x and y at A and B respectively . a triangle APQ is inscribed in the triangle OAB, O being the origin , with right angle at Q, P and Q lie respectively on OB and AB . if the area of the triangle APQ is 3/8th of the area of the triangle is what?

Dear Student,
Please find below the solution to the asked query:​

x+y=px/p+y/p=1

Length of X-axis intercept=p


Length of Y-axis intercept=p

Area ofOAB=1/2×X-axis intercept×Y-axis intercept

Area ofOAB=1/2×p×p= p2/2 unit2

Given thatArea ofAPQ=3/8×Area ofOABArea ofAPQ=3/8×p2/2Area ofAPQ=3/16p2 unit2


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