Login

the magnetic moment of a 3dseries elements ion is 5.92 BM. calculate the number of unpaired electrons

Given,

35 =n(n+2)35 = n(n+2) n = 5         

An ion (X3+) in 3d series of transition elements with 5 unpaired electrons has following electronic configuration:
1s22s22p63s23p63d5  = 23 electrons

So the element has an atomic number of 23+3 = 26

  • 6
View Full Answer
Here , magnetic moment is given by
Mu = root ( n( n+2) ) = 5.92                 ...................(1)

Only for n = 5 , the equality  (1)  holds good as root( 5 * (5+2 )  )= root( 5*7) = root(35) = 5.92.
So the number of unpaired electrons is 5. Hope that helps.

 
  • 9
What are you looking for?