The magnitude of acceleration of a point on the wheels rim at t= 1s whose radius is 2m and is spinning with angular velocity 'w' that varies with time as w = 10t^2a. 40root 26m/s^2b. 40 m/s^2c. Zerod. 20m/s^2 Share with your friends Share 2 Manoj Naranyanrao Dhage answered this 11 View Full Answer Shreyamishra answered this I need this solution -5 Mandeep answered this 40√26m/s2 3