The magnitude of the earth's magnetic field at a place is B0 and the angle of dip is δ. A horizontal conductor of length ℓ lying along the magnetic north-south moves eastwards with a velocity v. The emf induced across the conductor is :-
(1)    Zero
(2)    B0ℓv sin δ
(3)    B0ℓv
(4)    B0ℓv cos δ

Dear Student ,
When the conductor is lying along the magnetic north - south moves eastward and it will cut vertical component of B0 .
So the induced emf is ,
e=vBverticall=vB0sinδl=B0lv sinδ

  • 8
Answer d
  • -6
What are you looking for?