The mass of 70% H2SO4 required for neutralization of 1 mole of NAOH is Share with your friends Share 8 Geetha answered this 2 NaOH + H2SO4 → Na2SO4 +H2OFor 1 mole of NaOH the H2SO4 required = 0.5 mole 1 mole of H2SO4 = 98 g0.5 mole of H2SO4 = 49 g70 % H2SO4 required for 1 mole of NaOH = 4970 × 100 = 70 g 48 View Full Answer
