the mass of a thin uniform rod is 200gm and its length is 10cm. find its moment of inertia and radius of gyration about an axis passing through its midpoint and perpendicular to its length 

Dear student,

Moment of inertia of the rod passing through its centre and perpendicular to its length is 
 I = ML212Given M = 200 gm = 0.2 kgL = 10 cm = 0.1 mI = 0.2 ×0.1212=1.67×10-4kgm2Radius of gyrration K =IM=1.67×10-40.2=0.028

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