The maximum amount of BaSO4 (in terms of moles) precipitated on mixing equal volumes one litre each of BaCl2 (0.5M) with H2SO4 (1M) WILL CORRESPOND to
1)7kg
2)21kg
​3)14kg
4)28kg

1. The options provided by you are all in kg,and incorrect too. In question it is asked that amount BaSO4 in terms of moles.
2. The reaction is :

        BaCl2 + H2SO4   BaSO4 + 2HCl

3. 1 mole of BaCl2 reacts with 1 mole of H2SO4 to give 1 mole of BaSO4.
    But here 0.5 M of BaCl2 is present for 1 mole of H2SO4.
So.BaCl2 is the limiting reagent,and 0.5M of BaSO4 is obtained.

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