The maximum amount of BaSO4 (in terms of moles) precipitated on mixing equal volumes one litre each of BaCl2 (0.5M) with H2SO4 (1M) WILL CORRESPOND to
1)7kg
2)21kg
3)14kg
4)28kg
1. The options provided by you are all in kg,and incorrect too. In question it is asked that amount BaSO4 in terms of moles.
2. The reaction is :
BaCl2 + H2SO4 BaSO4 + 2HCl
3. 1 mole of BaCl2 reacts with 1 mole of H2SO4 to give 1 mole of BaSO4.
But here 0.5 M of BaCl2 is present for 1 mole of H2SO4.
So.BaCl2 is the limiting reagent,and 0.5M of BaSO4 is obtained.
2. The reaction is :
BaCl2 + H2SO4 BaSO4 + 2HCl
3. 1 mole of BaCl2 reacts with 1 mole of H2SO4 to give 1 mole of BaSO4.
But here 0.5 M of BaCl2 is present for 1 mole of H2SO4.
So.BaCl2 is the limiting reagent,and 0.5M of BaSO4 is obtained.