the maximum number of electron having n x l x m = 0 in Zn2+ is what?
Dear Student,
The electronic configuration of Zn2+ is
1s2 2s2 2p6 3s2 3p6 3d10 4s0
For n x l x m = 0, if either of them is equal to zero the multiplication of them is = 0.
From above orbitals, the electrons from 1s2 2s2 3s2 have l = 0, so their multiplication is also 0, so all the 6 electrons in this set is = 0.
from 2p6 3p6 3d10 , each orbitals has one electron which has m = 0, since m varies from m = -l to +l. So there are 3 electrons in this set which has n x l x m = 0.
Therefore, in total we have 9 electrons in Zn2+ which have n x l x m = 0.
Best wishes !
The electronic configuration of Zn2+ is
1s2 2s2 2p6 3s2 3p6 3d10 4s0
For n x l x m = 0, if either of them is equal to zero the multiplication of them is = 0.
From above orbitals, the electrons from 1s2 2s2 3s2 have l = 0, so their multiplication is also 0, so all the 6 electrons in this set is = 0.
from 2p6 3p6 3d10 , each orbitals has one electron which has m = 0, since m varies from m = -l to +l. So there are 3 electrons in this set which has n x l x m = 0.
Therefore, in total we have 9 electrons in Zn2+ which have n x l x m = 0.
Best wishes !