the maximum tension that an inextensible ring of mass density 0.1 kg/m can bear is 40 N.the maximum velocity with which it can be rotated in a circular path?

Let ‘r’ be the radius of the ring.

Mass per unit length of the ring is, ρ = 0.1 kg/m

Let the maximum linear speed of rotation be ‘v’.

So, mv²/r = 40

=> (2πr X ρ)(v²)/r = 40

=> 2πρv² = 40

=> (2)(3.14)(0.1)v² = 40

=> v² = 63.69

=> v = 7.9 m/s