the mean of 5 number is 18 if one number is excluded, their mean is 16 .find the excluded number

The mean of 5 numbers is 18

therefore the sum of 5 observations is 90

let the excluded number be x

therefore the sum of 4 observations is 90 - x

now,

the new mean = 16(given)]

therefore the sum of observations excluding that number = 16*4

  = 64

A/Q

90 - x = 64

-x = -26

x = 26

therefore the excluded number is 26

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x/5=18......so   x=18x5=90 

x/4=16.....so x=16x4=64

so excluded number is 90-64=26

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26
 
  • -5
The roots of equation 32x-10.3x+9=0
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( 1+ cotA +tanA) (sinA- cosA) =sinA tanA - cotA cosa
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26 is the answer
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Mean of 5 numbers is 18. So number is 18 multiple by 5 =90 . when one number is excluded then 4 multiple by 16. =64.
Excluded number is 90-64=26
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