THE MEAN OF THE FOLLOWING DISTRIBUTION IS 132 AND THE SUM OF THE OBSERVATION IS 50. FIND THE MISSING FREQUENCIES f1 AND F2.

Class Interval

xi

Frequency(fi)

ui=(xi-140/40)

fiui

0-40

20

4

-3

-12

40-80

60

7

-2

-14

80-120

100

f1

-1

-f1

120-160

140

12

0

0

160-200

180

f2

1

f2

200-240

220

9

2

18

 

720

=32+f1+f2

 

=-8 –f1+ f2

 

Sum of frequency = 32+f1+f2

Also sum of frequency  = 50  (given)

Therefore,

32+f1+f2= 50

f1+ f2= 18…………………….(i)

Mean = 132 (Given)

  • 2

 sory the class are 0-40,40-80, 80-120, 120-160, 160-200, 200-240

frequencies are 4 ,7, f1 ,12, f2, 9 pls help me

  • 4

F1 = 26 and F2 = -8  Hope It Helps You

  • -3
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