The measure of angle of elevation of top of tower 75√3 m high from a point at a distance of 75m from foot of tower in a horizontal plane is:



Let AB be the tower. Let C be the point of observation.Let ACB = θNow, AB = 753 m; BC = 75 mtan θ = perpendicularbase = ABBCtan θ = 75375tan θ = 3θ = 60°

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