The median of the following data is 52.5. find the value of x and y, if the total frequency is 100.

Class Interval 0-10 10-20 20-30 30-40 40-50 50-60 60-70 70-80 80-90 90- 100

frequency 2 5 X 12 17 20 Y 9 7 4

fi          Cf
2           2
5           7
x           7+x
12         19+x
17         36+x
20         56+x
y           56+x+y
9           65+x+y
7           72+x+y
4           76+x+y
100       x+y=24
 x+y=24 .......... (1)                                                  (given sum of frequency is 100)

Median=52.5
So the median class will be 50-60              

Applying the formula of median on class 50-60

l=50
N/2=50      (given N=100)
F=36+x
h=10
f=20

After applying the formula you will get value of x=9 and then substitute the value of x in eq. 1 you will get the value of y as 15





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