the median of the numbers of a patients attending a hospital is 36 , then find the missing of following - Maths - Statistics

Question

the median of the numbers of a patients attending a hospital is 36
, then find the missing of following frequency , when it is given
that the total number of days is 100
no of patients no of days
0-10 5
10-20 12
20-30 f1
30-40 f2
40-50 15
50-60 11
60-70 14

Rishabh Mittal · Accepted Answer

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57+f1+f2=100f1+f2=43   
1As median is 36 , so median class is 30-40
So,l=30 , f=f2 , cf=17+f1 and h=10
n=100 , n2=50
Median=l+n2-cff×h36=30+50-17-f1f2×1036-3010=33-f1f26f2=330-10 f110f1+6f2=3305f1+3f2=115   
2From 1f2=43-f1Substituting the value of f2 in 2 , we get5f1+343-f1=1155f1+129-3f1=1152f1=-14f1=-7Frequency can't be negative
So , question is wrong

the median of the numbers of a patients attending a hospital is 36 , then find the missing of following frequency , when it is given that the total number of days is 100. no. of patients no.of days 0-10 5 10-20 12 20-30 f1 30-40 f2 40-50 15 50-60 11 60-70 14

the median of the numbers of a patients attending a hospital is 36 , then find the missing of following frequency , when it is given that the total number of days is 100.
no. of patients no.of days
0-10 5
10-20 12
20-30 f1
30-40 f2
40-50 15
50-60 11
60-70 14