The minimum distance through which one tube, in a Quincke's tube, is to be shifted within the other, in order to get two such positions when no sound is heard, is 16.6 cm.Determine the frequency of the source of sound. Speed of sound in air=332 ms-1

Dear Student,

λ2=Distance between 2 consequtive maximas or minimas.Point of no sound is a minimaor λ=2×16.6=33.2 cm=0.332 mf=vλ3320.332=1000 Hz

Regards.

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