the molality of pure gas A is 25/1.1 and pure gas B is 100/6.4. now a gaseous solution was prepared by mixing pure gas A and B. the molarity of gas A in gaseous solution at 10 atm and 200/0.821 K temperature is 0.1 M. find molality of gas a in the solution

1. The formula for molarity change after mixing of two components is applicable in gaseous phase also.

2. So.assuming that equal volumes of gases A and B,say V are mixed in gaseous phase.

3. Calculation :

M = MAVA + MBVbVA +VB=MAV + MBV2V=MA + MB2=251.1+1006.42=19.17 M

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