THE MOLAR CONDUCTANCE OF 0.01N. SOLUTION OF H2SO4 AT 298 K IS 420 Scmsquare mol-1. calculate the resistance of the solution if the electrodes in the cell are 2cm apart having area of cross section 4cmsquare?
how we will solve this question ? BY USING WHICH FORMULA?
Λm = 420 S cm2 mol-1
C = 0.01 N.
For H2SO4, Basicity = 2
So, Molarity = 0.01 x 2 = 0.02 M
l = 2 cm
A = 4 cm2
Resistance of the solution can be calculated as:
