the monthly incomes of aryan and babban are in the ratio 3:4 and their monthly expenditure are in the ratio 5:7 . if each saves Rs 15000 per month,find their monthly incomes using matrix method.

Let the monthly incomes of Aryan and Babban be 3x and 4x, respectively.

Suppose their monthly expenditures are 5y and 7y, respectively.

Since each saves Rs 15,000 per month, 

Monthly saving of Aryan: 3x-5y=15,000Monthly saving of Babban: 4x-7y=15,000

The above system of equations can be written in the matrix form as follows:

3-54-7xy=1500015000

or,
AX = B, where A=3-54-7, X=xy and B=1500015000

Now,

A=3-54-7=-21--20=-1

Adj A=-7-453T=-75-43

So, A-1=1AadjA=-1-75-43=7-54-3

X=A-1Bxy=7-54-31500015000xy=105000-7500060000-45000xy=3000015000x=30,000 and y=15,000

Therefore,

Monthly income of Aryan = 3×Rs 30,000=Rs 90,000

Monthly income of Babban = 4×Rs 30,000= Rs 1,20,000 
 

  • 111
Take income as x and expenditure as y.
Now aryan incomes 3x and babban 4y.
Their expenditures are 5y and 7y.
The equations are
3x-5y=15000
4x-7y =15000
Solve it now.
  • -18
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