The moon has a period of 28 days and an orbital radius 3.8x105km. What is the orbital radius of a satellite that has a period of one day?

Dear Student,
Please find below the solution to the asked query:
 The square of the time-period is proportional to cube of the orbital radius:T2 α R3R2R13=T2T12R2R1=T2T123R2=R1×T2T123     =3.8×105×12823     =4.1×104 days
Hope this information will clear your doubts about Gravitation.
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