the no of hcl molecules present in 1cm^3 of its 1M solution is? Share with your friends Share 0 Yasodharan answered this Dear Student, The computation are expressed below, 1 cm3 = 1 ml = 0.001 ltby STP,22.4 lt contains 6.022×1023 moleculesso for 0.001 lt the molecule is, = 6.022×102322.4×0.001 = 2.688×1019 molecules Regards. 2 View Full Answer Syeda Afra answered this 6.022*10^23 1 Pushkar answered this 2.688×10^21 1
