The normal chord of the parabola y^2 = 4ax at (x1,x1) subtends a right angle at 1) focus 2) vertex - Maths - Conic Sections

Question

The normal chord of the parabola y^2 = 4ax at (x1,x1) subtends a
right angle at 1) focus 2) vertex 3) end of latus rectum 4) none of
these

Rdx · Answer

watch square equals to 4 x 14 x 1 X 1 / X 1 bracket X 1 - 4 age
bracket close = 20 employees X 1 = 20, 48 therefore point is 4, 4,
4 equals to 280 employees 2 equals to 30 equation of normal y = 2 -
2 X + 12 a m putting value of Y in equation of parabola we get X =
24 a common 9 am putting 9A is equation 1 we get y = 2 - 6 a slope
of PH = 4 a minus zero upon 4 minus 8 equals 4 upon 3 = M1 slope of
us = - 6

The normal chord of the parabola y^2 = 4ax at (x1,x1) subtends a right angle at 1) focus 2) vertex 3) end of latus rectum 4) none of these