The normality of a 1 3.42g L?
aluminium sulphate solution is :
(Molecular mass of aluminium sulphate = 342 gm/mole)
(1) 0.01 N (2) 0.03 N (3) 0.06 N (4) None of these

Dear student,

you have given the value 3.42 g/L which is the normality ( by SI units ), I guess you are asking for molarity then.

molarity * molar mass = normality
molarity = 3.42/342
molarity = 0.001 M

(1) is the correct option

OR

If 3.42 mol/L is the molarity then
normality = molar mass *molarity
normality = 1169.64 N

(4) is the correct option

Regards