the nth term of an AP is given by an= 4n - 5,then find the sum of first 25 terms of the AP.
if n=1
an= 4(1)-5 =-1
if n=2
an=4(2)-5 =3
therefore a= -1 ,a2= 3.... is the ap
d= 3-(-1) = 4
if n=25
an=4(25)-5 = 95
S25= n/2(a+an)
25/2(-1+95)
25/2(94) =25(47)=
1175
there fore th e sum of first 25 no og the ap will be 1175.
hope it helps
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