the number 87120 is not a perfect square. find the smallest number by which it should be multiplied to make it a perfect square. alsofind the number which should be added to make it a perfect square.

87120 = (2x2) (2x2) (3x3) (11x11) x5

Hence, the smallest number by which 87120 should be multiplied to get a perfect square is 5.

 

 

 

2 9 5

2

49

585

  3 0 2 0

  2 9 2 5

 

  95

So, the quotient is 295 and remainder is 95. Thus, it is evident that

 2952 < 87120 < 2962

2962 = 87616

2952=87025

87616-87025=591 

Thus, 591 must be added to 87120 to get a perfect square.

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87120  

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223+45

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hey robin this is easy. u can write 87120 in terms of its prime factors as 24*51*32*112

now 3 and 11 have power 2.

2 has power 4 (which is a multiple of 2)

but 5 has power 1. so if we multiple by 5 it will also have a power 2 and the final number will become a perfect square.

so we need to multiply 87120 by 5 = 435600

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the number 87120 is not a perfect square.

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  87120 = (2x2)(2x2)(3x3)(11x11)x5

hence the smallest number by which 87120 should be multiplied and added to get a perfect square is 5 

87120 x 5 = 2 x 2 x 2 x 2 x 3 x 3 x 11 x 11 x 5 x 5

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sorry it should not be added to 5 it would only be multiplied by 5. d correct answer is

first we'll find the square of the 87120. so the quotient of this is 295 and remainder is 95

thus it is evident that 2952 < 87120 < 2962

2962 = 87616

2952=87025

87616-87025=591 thus 87120 should be added to 591 to get a perfect square 

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5

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GIVEN NUMBER= 87120 =  2 * 2 * 2 * 2* 3* 3* 11* 11* 5

AFTER ARRANGING EQUAL PRIME FACTORS INTO TRIPLET FORM, ONE FACTOR OF 5 IS LEFT OUT.

 

TO MAKE IT INTO PAIR FORM, ANOTHER 5 HAS TO BE MULTIPLIED.

HENCE, THE LEAST NO TO BE MULTIPLIED= 5

 SORRY, THE LONG DIVISION IS NOT POSSIBLE TO BE DONE HERE.:))

HOPE THIS HELPS:))

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