The number of degenerate orbitals present in an energy level of H-atom characterized by E=-R/16 where R is the Rydberg constant ?
So if n2 = 16
n = 4
n is the principal quantum number. It means we have to find out the number of orbitals at energy level =4
Number of orbital is find out by 2l + 1 rule.
For n = 4 , possible value of l = 0 to 3
Number of orbital when l =0 is (2 x 0 +1 ) = 1
Number of orbital when l = 1 is (2 x 1 +1 ) = 3
Number of orbital when l = 2 is (2 x 2 +1 ) = 5
Number of orbital when l = 3 is (2 x 3 +1 ) = 7
So, total sixteen orbital.
Note here that we are calling total 16 orbital. Generally degenarate orbital is the term used for orbital with equal energy like px, py and pz or 5 -d orbitals etc.