The number of electrons involved in the reduction of nitrate ion to hydrazine is
A)8
- B)
7
- C)
5
- D)
3
Nitrate on reduction by acid produce hydrazine.
2NO3- + 16H+ + 14e- → NH2-NH2 + 6H2O
For reduction of two nitrogens 14 electrons are necessary.
So number of electron change per nitrogen is 14/2 = 7
So B) is the correct answer.
2NO3- + 16H+ + 14e- → NH2-NH2 + 6H2O
For reduction of two nitrogens 14 electrons are necessary.
So number of electron change per nitrogen is 14/2 = 7
So B) is the correct answer.