the number of elements in the set{(a,b)/ 2a^2+3b^2=35,a,b ?z}. When z is the set of all integers.

Dear Student, here is answer.
2a2+3b2=353b2=35-2a2b = ±1 or ±3so, if b = ±1, then 2a2=35-3=32a2=322=16a=±4and if b = ±3, then 2a2=35-27=8a2=82=4a=±2(4,1) (4,-1) (-4,1) and (-4,-1)(2,3) (2,-3) (-2,3) and (-2,-3)
Hence,there are 8 no. of elements.

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