the number of sulphate ion present in 3.92 g of chromium sulphate
Dear Student
In Chromium Sulphate, Cr2(SO4)3, there are 2 moles of chromium ions and 3 moles of sulphate ions
We know, No. of moles =
Molar Mass of Cr2(SO4)3 = 392 g/mol
Therefore, no. of moles in 3.92 g of Cr2(SO4)3 = = 0.01 mol
So, no. of moles of Chromium ions = (2 x 0.01) moles = 0.02 mol
No. of moles of Sulphate ions = (3 x 0.01) moles = 0.03 mol
Total no. of ions/molecules of sulphate = no. of moles x Avagadro number
= 0.03 x 6.023 x 1023 = 0.18069 x 1023 = 1.8069 x 1022
Regards
In Chromium Sulphate, Cr2(SO4)3, there are 2 moles of chromium ions and 3 moles of sulphate ions
We know, No. of moles =
Molar Mass of Cr2(SO4)3 = 392 g/mol
Therefore, no. of moles in 3.92 g of Cr2(SO4)3 = = 0.01 mol
So, no. of moles of Chromium ions = (2 x 0.01) moles = 0.02 mol
No. of moles of Sulphate ions = (3 x 0.01) moles = 0.03 mol
Total no. of ions/molecules of sulphate = no. of moles x Avagadro number
= 0.03 x 6.023 x 1023 = 0.18069 x 1023 = 1.8069 x 1022
Regards