the number of ways in which thirty five apples can be distributed among 3 boys so that each can have any number of apples

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The question should be; 
The number of ways in which thirty five apples can be distributed among 3 boys so that each can have any number of apples
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Number of ways=37C2=37!35!×2!=666 waysFor the distribution equation x1+x2+x3+...+xr=nThe  number of ways  in which n things can be distributed among r in such a way each can receive none one or more or all of n items are n+r-1Cr-1
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