The number of ways that all the letters of the word SWORD can be arranged such that no letter is on its original position is ??

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Please find below the solution to the asked query:

SWORDThis is simple question of derangement of 5 objects.S,W,O,R,DFormula for derangement of n objects is:S=n! 1-11!+12!-13!+...HenceS=5!1-11!+12!-13!+14!-15!=5!12!-13!+14!-15!=12012-16+124-1120=60-20+5-1=44 Answer

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