The outer and inner diameters of a hemispherical bowl are 17cm and 15cm find the cost of polishing it over at 25 paise per cm2 Share with your friends Share 2 Varun.Rawat answered this We haveexternal dimater = D = 17 cmExternal radius = R = D2 = 172cmInternal diamter = d = 15 cmInternal radius = r = d2 = 152 cmNow,area to be polished = 2πR2 + 2πr2 + πR2 - r2=π2R2 + 2r2 + R+rR-r=2272 × 2894 + 2 × 2254 + 16 × 1=2272892 + 2252 + 16=227289+225+322=227 × 5462=858 cm2Cost of polishing 1 cm2 area = Re 0.25So, cost of polishing 858 cm2 area = Rs 0.25 × 858 = Rs 214.50 4 View Full Answer
