The perimeter of a rectangular field is 32m 30cm. The ratio of its length to that of its breadth is 10:7. Find its dimension.

Since the ratio of its length to that of its breadth is 10 : 7.
so suppose the length and breadth of the rectangular field are 10x and 7x respectively.
So, the perimeter of triangle = $2\left(10x+7x\right)$ = 32 m 30 cm = $32\times 100+30$ = 3230 cm
$$\begin{gathered} \Rightarrow 2\times 17x = 3230 \\ \Rightarrow 34x = 3230 \\ \Rightarrow x = \frac{3230}{34} = 95 \end{gathered}$$
So length of the rectangular field = $10\times 95 = 950 \mathrm{cm}$
And width of the rectangular field = $7\times 95 = 665 \mathrm{cm}$