The perimeter of a.rhombus is 192 cm. The lenghts of its diagonal are 60 and 80 cm. Findthe perpendicular distance from the opposite sides.

The answer is 50 cm. Because the area of rhombus will be 1/2 *60 *80= 2400cm2 And area of rhombus is also equal to b*h Then 2400 = 48h H=50 Ps:48 is the value of each side as 4a = 192.
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