The pH of solution at 25°C which has twice as many hydroxide ion as in pure water at 25°C will be

7.301
  • -3

no of hydroxide ion in pure water = 10-7

so according to the given condition no. of hydroxide ions in solution = 2*10-7

so pOH = -log2*10-7

so pH = 14 - pOH 

  • 34
try this

  • 13
Answer is 7.301

  • -1
Answer

  • 4
This is the solution :

  • 1
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