the phase difference between current and voltage in an AC circuit is pie/4 radian . if the frequency of AC is 50Hz, then the phase difference is equivalent to the time difference of

1) 0.75s

2) 10.5ms

3) 2.5ms

3) 0.25ms

Question

the phase difference between current and voltage in an AC
circuit is pie/4 radian if the frequency of AC is 50Hz, then the
phase difference is equivalent to the time difference of
1) 0 75s
2) 10 5ms
3) 2 5ms
3) 0 25ms

Neha Gupta · Accepted Answer

Frequency of an AC = 50 Hztime period = 150 = 0
02 s2π radian has time period is equal to 0
02 sπ4 radian has time period = 0
022π×π4 = 0 0025 s= 2
5 ms

Hence option(3) is correct

the phase difference between current and voltage in an AC circuit is pie/4 radian . if the frequency of AC is 50Hz, then the phase difference is equivalent to the time difference of 1) 0.75s 2) 10.5ms 3) 2.5ms 3) 0.25ms

the phase difference between current and voltage in an AC circuit is pie/4 radian . if the frequency of AC is 50Hz, then the phase difference is equivalent to the time difference of

1) 0.75s

2) 10.5ms

3) 2.5ms

3) 0.25ms