the point A (3,y) is equidistant from points P (6,5) and Q (0,-3) find value of y

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  • -1
AP = AQ 
Using distance formula -
(6 - 3)2 + (5 - y)2 = (0 - 3)2 + (-3 - y)2
9 + 25 + y- 10y = 9 + 9 + y+ 6y
25 - 10y = 9 + 6y
16 = 16y 
y = 1
 
  • 16
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