The population of a city increases each year by 4% of what it had been at the beginning of each year. If its present population is 6760000 ,find: (1) its population 2 years hence (2)its population 2 years ago.
Dear student,
Population increase=4%
Again,
Regards
Population increase=4%
present population= 6760000
1)
4%of 6760000
4%of 6760000
=4/100*6760000
=27040
Population after 1 yr
=27040
Population after 1 yr
=6760000+27040
=6787040
Population after 2 yr
=6787040
Population after 2 yr
=6787040+(4/100*6787040)
=7058522(approx)
=7058522(approx)
Again,
present population= 6760000
4% of 6760000=27040
Population 1yr ago
Population 1yr ago
=6760000-27040
= 6732960
Now
= 6732960
Now
4% of 6732960
=269318.4
Population 2yr ago
=269318.4
Population 2yr ago
=6732960-269318.4
=6463642(approx)
Regards