The position coordinates of an object are given by x= 2t2 , y=t2-4t, z=3t-5. The average velocity of the particle during the interval 0.1 sec is?

I think the question is wrong as the answer is given as root22. Can you please rectify the question?????????????

x = 2t2  , y = t2   , z= 3t-5t = 0.1therefore x = 0.02y = 0.01z = -4.7distnace travelled = d = x2+y2+z2d = 22.0905Avg velocity = dt = 22.09050.1 = 2209.05 m/s

  • -47
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